Domestic Wind Turbines Blog » VERTICAL WINDMILL

Do I need to see a psychalogist?

admin — Thu, 24 Feb 2011 07:10:29 +0000

I love basketball and I’m pretty good. Whenever I play in public I get extremely scared and I do bad. Becuase of that I couldnt make any basketball team but I’m very good. This fear has been a problem for a long time. This fear is irrational because I know I’m very good at basketball and very athletic. I have a 35 inch vertical leap and I can do a windmill slam dunk and I’m 6′3. I’m a good ball handler and a good shooter. Most people that I know had the same fear I do easily overcame it. Do you think I have a serious problem? Like a phobia. Most people that have seen me play basketball in private think I’m a prospect. What should I do? Should I see a psychalogist? I really think I should.

If you think, why are you not sure about it?
I think it’s all just in you, find what’s going on, eat well, and solve your problems and everything will be alright. Bless you.

to be able to dunk windmills, 360 and between the legs being 6′2. what is your vertical leap suppose to be at?

admin — Sun, 16 Jan 2011 12:40:31 +0000

am 6′2 can dunk normal with a 24′ in vertical.

gotta have mad hops

What do you think my potential is?

admin — Sat, 18 Dec 2010 23:08:38 +0000

The vertical leap test determines ultimatlety how athletic an athlete is and the average nba vertical leap is 28 inches. I’m 15 and my vertical leap is 31 inches( I’m not lying, if I was lying, this question would be pointless ). I’m just barely above the average NBA athlete in terms of athleticism. I have somewhat of a natural ability to control the ball. I not very skilled but I am very athletic and I have good handles. I’m 6′3 and 185 lbs. I can do tons of dunks. I can windmill and other crazy dunks. Since I’m only 15 and I have some handles( although overall I’m not very skilled) and I have a little more athletecism than the average nba player does that mean that with proper training and hard work I can at least be a good D1 balla?
By the way, Dwayne Wade’s vertical leap is 31.5 inches.

i think you’re ready. you should contact some European teams and make some money.

if all else fails the yankees will probably pay you too much money to do too little.

Tricky physics homework problem…?

admin — Fri, 17 Dec 2010 03:14:45 +0000

A softball pitcher has a windmill wind up in which a 0.25 kg ball moves on a vertical arc of radius r = 0.51 m. To accelerate the ball, she exerts a 28 N force parallel to the ball’s motion along the circular arc. The speed of the ball is 12 m/s at the top of the arc. With what speed is the ball released one half a revolution later at the bottom of the arc?

The radius r = 0.51 m

mass of ball m = 0.25 kg

Force on ball (F) = 28 N

Acceleration of ball due to force exerted by player (a) = F/m = 28/0.25
= 112 m/s^2

v (speed of ball) at top of arc (180 degrees) = 12 m/s

Therefore time it takes to go 180 degrees = v/a = 12 / 112
= 0.1071 s

Therefore time it takes for ball to make another 180 degrees before release (t) = 0.1071*2 s = 0.2142 s

a = 112 m/s^2

speed of ball at release = a*t = (112 * 0.2142) m/s = 24 m/s

Who would like to help me with my Physics Question?

admin — Wed, 15 Dec 2010 06:20:35 +0000

A fastpitch softball player does a "windmill" pitch, moving her hand through a vertical circular arc to pitch a ball at 66 mph. The 0.19 kg ball is 53 cm from the pivot point at her shoulder.

A) Just before the ball leaves her hand, what is its centripetal acceleration?

B) At the lowest point of the circle the ball has reached its maximum speed. What is the magnitude of the force her hand exerts on the ball at this point?

C) At the lowest point of the circle the ball has reached its maximum speed. What is the direction of the force her hand exerts on the ball at this point?

Centripetal acceleration is V^2/R
V = 66 mph which has to be converted to km/h or m/s or whatever units you are interested in. I would use meters, etc since the are is 0.53 m and the ball is 0.19 kg.

At the lowest point, gravity is pulling down on the ball and her hand must compensate for this. It must also produce the force necessary to provide the centripetal acceleration for the ball to maintain the circular motion.

Centripetal force = m*V^2/R
Gravitational force = m*g

Force exerted by arm = m*V^2/R + m*g = m*[V^2/R + g]

At the lowest point gravity is acting downwards so the force of her hand will be directed upward. The force necessary to maintain an object in constant circular motion is directed perpendicular to the circumference of the circle.

Verticle leap?

admin — Mon, 13 Dec 2010 05:08:54 +0000

How can I increase my vertical leap? I want to be able to throw down a windmill by the end of next May. My height it 6′2" and my weight is 180 pounds. Also, right now I am able to do a two handed dunk just by taking only 3 steps. And my vert is approx around 38-41 inches. How many more inches is a windmill? Ive tried completing one 34 times once and I just couldn’t do it.

do calf raises and if you want u can even try programs such as air alert. If this is not good for you, the website below has great drills that will help u wit your vertical leap

I really need your help with this physics problem please explain how you get your answer thanks!!?

admin — Sat, 11 Dec 2010 05:35:27 +0000

A fast pitch softball player does a "windmill" pitch, moving her hand through a vertical circular arc to pitch a ball at 68mph . The 0.19kg ball is 51cm from the pivot point at her shoulder.
Just before the ball leaves her hand, what is its centripetal acceleration?
At the lowest point of the circle the ball has reached its maximum speed. What is the magnitude of the force her hand exerts on the ball at this point?
At the lowest point of the circle the ball has reached its maximum speed. What is the direction of the force her hand exerts on the ball at this point?

Centripetal acceleration is given by

a = v^2/R

so R = 0.51 m
and v = 68 mph = 30.4 m/s

a = 1812 m/s^2

Since just before the point of release there is no acceleration along the arc, the only acceleration is towards the centre (shoulder pivot).

So, F = ma

= 0.19 x 1812 = 344 N

Do I need to see a pyschalogist?

admin — Thu, 09 Dec 2010 03:06:02 +0000

softball pitch physics ?

admin — Tue, 07 Dec 2010 05:49:23 +0000

A fast pitch softball player does a "windmill" pitch, moving her hand through a vertical circular arc to pitch a ball at 75 mph. The 0.19kg ball is 52cm from the pivot point at her shoulder.
a)Just before the ball leaves her hand, what is its centripetal acceleration? In m/s^2
b)At the lowest point of the circle the ball has reached its maximum speed. What is the magnitude of the force her hand exerts on the ball at this point?

75 mph = 33.52 m/s

a) ac = V²/r = 33.52²/.52 = 2161 m/s²

b) at = (dv)²/(2*dx) = 33.52²/(2*2π*.52) = 171.95 m/s²;
atot = √(ac²+at²) = √(2161²+171.95²) = 2168 m/s²

F = m*atot = .19*2168 = 412 N

Who do you think is the best TFB(team flight brothers) dunker today.?

admin — Sun, 05 Dec 2010 07:12:45 +0000

I would say top 5 are.

1.Golden Child- Highest vert 50” Sick windmills with head over rim just 6′1

2.T-Dub- 5′9- shortestmember of team flight brothers dunkers unbelievable vertical

3. Justin Darlington- Best overall dunks in my opinion but hes 6′4

4. Guy Dupree

5. ???

Darlington should be 2nd. and T-Dub should be 3rd.